Wire diameter calculation
The n gauge wire diameter dn in millimetres (mm) is equal to 0.127mm times 92 raised to the power of 36 minus gauge number n, divided by 39:
dn (mm) = 0.127 mm × 92(36-n)/39
0.127mm is the diameter of gauge #36.
Wire cross-sectional area calculation
The n gauge wire’s cross-sectional area An in square millimetres (mm2) is equal to pi divided by 4 times the square wire diameter d in millimetres (mm):
An (mm2) = (π/4)×dn2 = 0.012668 mm2 × 92(36-n)/19.5
AWG | Diameter | Area | ||
(in) | (mm) | (mm2) | ||
0000 (4/0) | 0.4600 | 11.684 | 107 | |
000 (3/0) | 0.4096 | 10.405 | 85.0 | |
00 (2/0) | 0.3648 | 9.266 | 67.4 | |
0 (1/0) | 0.3249 | 8.251 | 53.5 | |
1 | 0.2893 | 7.348 | 42.4 | |
2 | 0.2576 | 6.544 | 33.6 | |
3 | 0.2294 | 5.827 | 26.7 | |
4 | 0.2043 | 5.189 | 21.2 | |
5 | 0.1819 | 4.621 | 16.8 | |
6 | 0.1620 | 4.115 | 13.3 | |
7 | 0.1443 | 3.665 | 10.5 | |
8 | 0.1285 | 3.264 | 8.37 | |
9 | 0.1144 | 2.906 | 6.63 | |
10 | 0.1019 | 2.588 | 5.26 | |
11 | 0.0907 | 2.305 | 4.17 | |
12 | 0.0808 | 2.053 | 3.31 | |
13 | 0.0720 | 1.828 | 2.62 | |
14 | 0.0641 | 1.628 | 2.08 | |
15 | 0.0571 | 1.450 | 1.65 | |
16 | 0.0508 | 1.291 | 1.31 | |
17 | 0.0453 | 1.150 | 1.04 | |
18 | 0.0403 | 1.024 | 0.823 | |
19 | 0.0359 | 0.912 | 0.653 | |
20 | 0.0320 | 0.812 | 0.518 | |
21 | 0.0285 | 0.723 | 0.410 | |
22 | 0.0253 | 0.644 | 0.326 | |
23 | 0.0226 | 0.573 | 0.258 | |
24 | 0.0201 | 0.511 | 0.205 | |
25 | 0.0179 | 0.455 | 0.162 | |
26 | 0.0159 | 0.405 | 0.129 | |
27 | 0.0142 | 0.361 | 0.102 | |
28 | 0.0126 | 0.321 | 0.0810 | |
29 | 0.0113 | 0.286 | 0.0642 | |
30 | 0.0100 | 0.255 | 0.0509 | |
31 | 0.00893 | 0.227 | 0.0404 | |
32 | 0.00795 | 0.202 | 0.0320 | |
33 | 0.00708 | 0.180 | 0.0254 | |
34 | 0.00630 | 0.160 | 0.0201 | |
35 | 0.00561 | 0.143 | 0.0160 | |
36 | 0.00500 | 0.127 | 0.0127 | |
37 | 0.00445 | 0.113 | 0.0100 | |
38 | 0.00397 | 0.101 | 0.00797 | |
39 | 0.00353 | 0.0897 | 0.00632 | |
40 | 0.00314 | 0.0799 | 0.00501 |